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2 years ago

The side of a square is 11.2 cm. what is the length of the diagonal

1 answer:

3 0

You can work out the diagonal by using Pythagoras theorem. (a^2 = b^2 + c^2)

As it is a square, all 4 sides are the same so it would be:
11.2^2 + 11.2^2 = diagonal^2
250.88 = diagonal^2
Square root both sides to get what the diagonal is equal to.
diagonal is 15.8 cm

You might be interested in

How do you simplify 36 over 10

Studentka2010 [4]

Answer:

18/5

Step-by-step explanation:

36/10

First find a number that goes into both the two numbers.

...2 can go into both of them...

36 / 10

(÷2) (÷2)

18 / 5

Now we have to see if any other number goes in to these new numbers...

There are no numbers that goes into both...

Hope this helped! <3

8 0

2 years ago

Solve for the variable: 12.9 = x + 7.1 5.8 -5.8 20 -20

olya-2409 [2.1K]

12.9 = x + 7.1
subtract 7.1 from both sides to isolate the variable, x.

5.8 = x

5.8 is your answer.

3 0

2 years ago

Valentin [98]

Answer 20 are left

Step-by-step explanation:

6 0

2 years ago

The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 .

Novosadov [1.4K]

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A; &

Let Claire be = C

A: C = 7 : 4

$\dfrac{A}{C} =\dfrac{7}{4}$

7C = 4A

$C = \dfrac{4A}{7}$ --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

$\dfrac{A}{C+68}= \dfrac{25}{41}$

25(C + 68) = 41A

C + 68 = $\dfrac{41}{25}A$

$C = \dfrac{41}{25}A - 68$ --- (2)

Equating (1) and (2) together;

$\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68$

$\dfrac{4 * A}{7}-\dfrac{41 *A}{25} = - 68$

$\dfrac{100A - 287 A}{175} =- 68$

$\dfrac{-187A}{175} = -68$

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; $C = \dfrac{4A}{7}$

$C = \dfrac{4*64}{7}$

C = 36.57

C ≅ 37 beads

4 0

2 years ago

You have 19 digs for your current volleyball season. There are 5 games left in the season. You want to break your previous recor

Charra [1.4K]

Answer:We must get more than 7 digs in the remaining 5 games to break record of 26.

Step-by-step explanation:

Given situation:- Let x represents the number of digs which we must get in the remaining 5 games to break your record ,and we have 19 digs for our current volleyball season.

To break previous record of 26 digs in a season, we have to get more than 26 i.e. 19 digs added to x must be greater than 26

⇒x+19 ≥ 26

⇒x≥26-19⇒x≥7

Therefore,we must get more than 7 digs in the remaining 5 games to break record of 26.

4 0

2 years ago