<h2>
Answer:</h2><h2>
The probability that Roy gives randomly an SUV = 15 / 47</h2>
Step-by-step explanation:
The total number of used cars owned by Roy = 47
[12 trucks + 20 cars + 15 SUV = 47 cars]
The total number in sample space, n (S) = 47
The probability that Roy is giving away and SUV = ?
Let A be the event that Roy is giving an SUV
Total no of SUV's , n (A) = 15
The probability of giving an SUV, P (A) = n (A) / n (S)
P (A) = 15 / 47
Answer: 272
Step-by-step explanation:
Let a1=11
a2=20
a3=29
Formula for sequence=
an=a1+(n-1)d
an = nth term
a1= first term
n= nth position
d= common difference
We are looking for the 30th term,so our n=30
d= a2-a1
d= 20-11
d= 9
Using the formula
an= a1+(n-1)d
a30= 11+(30-1)9
a30= 11+(29)9
a30= 11+(29×9)
a30= 11+261
a30= 272
Therefore, the 30th term is 272
Hello,
Equation is y=k(x-1)²-9
and when x=0,y=-6==>-6=k*1²-9==>k=3
y=3(x-1)²-9
when y=0, 3(x-1)²-9=0
==>(x-1-√3)(x-1+√3)=0
x-intercepts are (1+√3,0) and (1-√3,0)
Answer B.
Jack invested 57
Sam invested 38
57 over 38 minus 1,00