Answer:
V₀ = 5.47 m/s
Explanation:
The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:
R = V₀² Sin 2θ/g
where,
R = Range of Projectile = 3.04 m
θ = Launch Angle = 41.7°
V₀ = Minimum Launch Speed = ?
g = 9.81 m/s²
Therefore,
3.04 m = V₀² [Sin2(41.7°)]/(9.81 m/s²)
V₀² = 3.04 m/(0.10126 s²/m)
V₀ = √30.02 m²/s²
<u>V₀ = 5.47 m/s</u>
Answer: 888.45 K or 615.3 °c
Explanation:
According to Gay Lussacs law which states that at constant volume, pressure of an ideal gas is directly proportional to it's absolute temperature.
P/T = Constant
Therefore, P1/T1 = P2/T2
P1 = 6.7 atm
T1= 23°c = 273.15 + 23 = 296.15K
Since P2 is tripled, then,
P2 = 6.7 x 3= 20.1 atm
T2 = (20.1 x 296.15) ÷ 6.7
T2 = 888.45 K
Or in celcius 615.3°c
