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2 years ago

What would happen if the spindle fiber were cut before mitosis is completed

1 answer:

5 0

Would cause a dysfunction in the mitosis process of the cell, either the cell will redo its process of division.

<span>The two identical daughter cells resulting from mitosis and cytokinesis are identical in the following ways:1. Mitosis occurs when the nucleus of the cell divides into two identical nuclei, each with the same type and number of chromosomes. The cell's DNA is duplicated during this phase. Sometimes the cell's DNA isn't copied properly resulting in cancer-type cells. 2. Cytokinesis is when the cytoplasm divides into two identical daughter cells. Each cell is genetically identical and both are a similar size. </span>

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assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

6 0

2 years ago

Which of these is part of a feedback loop that results in a cooling effect on earth?

Dmitriy789 [7]

Answer: More evaporation of the water due to warmer temperatures causes low, thick clouds to form

Explanation:

8 0

2 years ago

What is unique about carbon?

amm1812

Bonding properties!!!

6 0

2 years ago

Two formal terms used to describe categories of mutational nucleotide substitutions in dna are ________.

mamaluj [8]

Transversion and transition

6 0

2 years ago

An enzyme contains a catalytic histidine residue in its active site that must release an R group proton to solution in order to

hjlf

Options missing:

a) The pH of the environment should be relatively high.

b) The pH of the environment should be relatively low.

c) The pH of the environment would not matter.

d) The environment should be set to the biochemical standard state.

Answer:

a) The pH of the environment should be relatively high.

Explanation:

For optimal function an enzyme needs a certain environment or condition. As temperature increases, the rate of enzyme activity also increases. As temperature increases toward its optimum point of 37 degrees Celsius (98.6 F), hydrogen bonds relax and make it easier for the hydrogen peroxide molecules to bind to the catalase.

The part of the enzyme where this reaction takes place is called the active site. A temperature that is higher or lower than this optimum point changes the shape of the active site and stops the enzyme from working. This process is called denaturation.

Enzyme pH levels also change the shape of the active site and affect the rate of enzyme activity. Each enzyme has its own optimal range of pH in which it works most effectively. In humans, catalase works only between pH 7 and pH 11. If the pH level is lower than 7 or higher than 11, the enzyme becomes denaturated and loses its structure. The liver sustains a neutral pH of about 7, which creates the best environment for catalase and other enzymes.

General acid catalysis would require histidine to be protonated at pH values (pH 8.0) optimal for enzymatic activity which is relatively high.

3 0

2 years ago