I can only give possible combinations of the ages. This is because only the product is given. Had the sum of all ages been given, possible combinations would boil down into 1 combination.
3 kids with a youngest. This means that the ages are not the same.
We do prime factorization to get the age combination.
72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 = 9
9 ÷ 3 = 3
3 ÷ 3 = 1
1 x 2 x 2 x 2 x 3 x 3 = 72
Possible combination with no repeating number.
1 x 8 x 9 = 72
2 x 4 x 9 = 72
4 x 6 x 3 = 72
1 x 6 x 12 = 72
Answer:
Area of shape B = 312.5 cm²
Step-by-step explanation:
Ratio of Area of A : Area of B = 12² : 15²
Given that area of A is 200 cm², let the area of shape B = x
Therefore:
200:x = 12²:15²
200/x = 144/225
Cross multiply
144x = 200*225
144x = 45,000
x = 45,000/144
x = 312.5 cm²
Area of shape B = 312.5 cm²
633,248.
The difference of each 3 is that they have different place values.
The 3 on the right side is int he 1000s (thousands) place, and the 3 on the left is in the 10,000s (ten thousands) place. :)
The one in the 10,000s place is 10 times larger than the one in the 1,000s place!
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
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