What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC
l to reach the 2nd end point
1 answer:
Answer:
0.109 g.
Explanation:
Equation of the reaction:
Na3PO4 + 3HCl --> 3NaCl + H3PO4
Number of moles of HCl = molar concentration × volume
= 0.1 × 0.04
= 0.004 mol.
By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3
= 0.0013 mol
Mass of Na3PO4 = molar mass × number of moles
= 0.0013 × 164
= 0.219 g
Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance
= 0.219 × 50 g/100 g
= 0.109 g.
You might be interested in
Answer:
you can solve the rest of the equation. I only reduced it to that much to show you how to derive it
Answer:
density = 2.769 g
Explanation:
4.26 times 0.65
I believe the answer is A
Electrons can flow freely in metals.
Yes it is for example look at Iodine and Tellurium.
Hope this helps :).
Answer:
B
Explanation:
The mantle is composed of the mesosphere and the asthenosphere in the upper most part and in the crust is the lithosphere
