The answer is false
Animals store carbohydrate's as glycogen is store in the muscle or liver. not in food. however, not a source of dietary carbohydrates.
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Answer:
a) The response indicates that a pH below or above this range will most likely cause enolase to denature/change its shape and be less efficient or unable to catalyze the reaction.
b)The response indicates that the appropriate negative control is to measure the reaction rate (at the varying substrate concentrations) without any enzyme present.
c)The response indicated that the enolase has a more stable/functional/correct/normal protein structure at the higher temperature of 55°C than at 37°C because the enzyme is from an organism that is adapted to growth at 55°C.
Explanation:
Enolase catalyzes the conversion of 2-phosphoglycerate to phosphoenolpyruvate during both glycolysis and gluconeogenesis.In bacteria, enolases are highly conserved enzymes and commonly exist as homodimers.
The temperature optimum for enolase catalysis was 80°C, close to the measured thermal stability of the protein which was determined to be 75°C, while the pH optimum for enzyme activity was 6.5. The specific activities of purified enolase determined at 25 and 80°C were 147 and 300 U mg−1 of protein, respectively. Km values for the 2-phosphoglycerate/phosphoenolpyruvate reaction determined at 25 and 80°C were 0.16 and 0.03 mM, respectively. The Km values for Mg2+ binding at these temperatures were 2.5 and 1.9 mM, respectively.
Enolase-1 from Chloroflexus aurantiacus (EnoCa), a thermophilic green non-sulfur bacterium that grows photosynthetically under anaerobic conditions. The biochemical and structural properties of enolase from C. aurantiacus are consistent with this being thermally adapted.
Mitosis cannot happen without cytokinesis. Mitosis is the process a cell goes through to produce 2 new cell nuclei. If mitosis happened but cytokineses did not, then one cell would have 2 nuclei in it. Cytokinesis is the splitting of the cytoplasm. If cytokinesis happened without mitosis taking place, then the cell would either be split at the nucleus and it wouldn't survive, or the cell wouldn't have any nucleus and it wouldn't survive.
Answer:
A is correct
Explanation:
Mendel's law of independent assortment states that alleles of a gene get separated or sorted into gametes independently of the alleles of
the other gene. In this case, two genes are involved, one coding for seed color (A) and the other for seed shape (B). Alleles A and B are dominant over alleles a and b respectively. Hence, a pea plant heterozygous for both genes will have a genotype AaBb.
According to Mendel's law of independent assortment, alleles A and a will randomly sort into gametes independently of alleles B and b. This will result in the production of four equally likely gametes with genotypes: AB, Ab, aB and ab. This shows that the gamete that receives the A allele will equally be likely to contain either B or b allele. The same applies for a allele as well.
Options B and D are wrong because it is not a must it occurs, it is just a possibility or likelihood that it does.
Option C is wrong because four equally likely combination of gametes are possible not two.
Option E is wrong because it does not conform to the law of independent assortment, in which both genes must be represented in each gamete.
