All categories

2 years ago

Is 52634275309 in standard form?

Mathematics

2 answers:

Viktor [21]2 years ago

5 0

Yes, that number is in standard form.

monitta2 years ago

5 0

52634275309 is already in standard form.

You might be interested in

Which equation correctly uses point (–2, –6) to write the equation of this line in point-slope form? Y – 6 = y minus 6 equals St

Tanya [424]

Answer:

Step-by-step explanation:

The standard way of writing equation of a line in a point-slope form is as given;

y - y0 = m(x-x0)

m is the slope of the line

(x0,y0) is a point on the line.

Given the point (-2,-6), in order to determine with of the equation that correctly uses the point, we will substitute the point into the formula and get the necessary equation.

y - y0 = m(x-x0)

y - (-6) = m(x-(-2))

y+6 = m(x+2)

Since we are not given the slope, let's assume the slope is 5/2

The equation becomes y+6 =5/2(x+2). Option D is correct

8 0

2 years ago

Angie opened a bank account. She deposited $225 each month for 4 months. Her bank charged her $5 each month to use the account.

Llana [10]

After 4 months Angie’s account would be $880

6 0

2 years ago

Tell what each variable you used represents. 1. Number of tickets 2 3 4 5 Total Cost ($) 54 81 108 135 a. Proportional? b. Equat

NNADVOKAT [17]

Answer:

Step-by-step explanation:

6 0

2 years ago

Find the area of the figure.<br> 9 mi<br> ורדן ס<br> 9 mi<br> 4 mi

Mariulka [41]

Answer:

5 mi

Step-by-step explanation:

6 0

2 years ago

n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t

givi [52]

Answer:

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

We use this equation to find the value of r.

In this problem, we have that:

$K = 16, P_{0} = 2, P(50) = 4$

So we find the value of r.

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

$4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}$

$4 = \frac{32e^{50r}}{14 + 2e^{50r}}$

$56 + 8e^{50r} = 32e^{50r}}$

$24e^{50r} = 56$

$e^{50r} = 2.33$

Applying ln to both sides of the equality

$50r = 0.8459$

$r = 0.017$

The differential equation is

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

3 0

2 years ago