Answer: 117.8 nm
Explanation:
Given,
Nonreflective coating refractive index : n = 1.21
Index of refraction: = 1.52
Wave length of light = λ = 570 nm =
Hence, the minimum thickness of the coating that will accomplish= 117.8 nm
Answer:
T=1.384×10⁶seconds
Explanation:
Given data
p (Intensity)=1.30 kw/m²
E (Energy)=1.8×10⁹ J
A (Area)=1.00 m²
T (Time required)=?
Solution
E=PT ................eq(i)
where E is energy
P is radiation power
T is time
Radiating Power is given as
P=pA
Where p is intensity
A is Area
Put P=pA in eq(i) we get
E=pAT
T=E/pA
Answer:
Spring constant, k = 5483.11 N/m
Explanation:
It is given that,
Mass of the organ, m = 2 kg
The natural period of oscillation is, T = 0.12 s
Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :
k = 5483.11 N/m
So, the spring constant for the spring in the scientist's model is 5483.11 N/m.