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2 years ago

- 2/3 × 3/5 + 5/2 - 3/5 × 1/6

Mathematics

2 answers:

elena-s [515]2 years ago

7 0

Answer:

Step-by-step explanation:

(-2/3 x 3/5) + 5/2 - (3/5 x 1/6)

-2/3 x 3/5 = -6/15 = -2/5 (simplified)

3/5 x 1/6 = 3/30 = 1/10 (simplified)

Changed equation: -2/5 + 5/2 - 1/10

-2/5 x 2 = -4/10

5/2 x 5 = 25/10

Changed equation: -4/10 + 25/10 - 1/10

Answer: 20/10 = 2 (simplified answer)

madam [21]2 years ago

5 0

First start by multiplying:
-6/15 + 5/2 -3/30

then u can simplify the fractions, -6/15=-2/5 and -3/30=-1/10

-2/5 + 5/2 - 1/10, now find a common denominator in this case 10
-4/10 + 25/10 - 1/10

now add and subtract normally

answer:20/10 or 2

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2 years ago

What is the following product? (4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$