Oxygen,carbon,hydrogen,and nitrogen- together make up 95 percent of the mass of the human body.
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40.6 kJ of heat energy had been emitted.
CO(g) + 2H2(g) CH3OH(l)CO volume, V (CO), equals 15 L or 0.015 m3.
Temperature = 85 0C = 85 + 273 = 358 K Pressure = 112 kPa = 112,000 PaPV = nRT n= 112000 0.015 / 8.314 358 n(CO) = 0.56 moles,
according to the ideal gas law.H2 volume is 14.4 L or 0.0144 m3
T = 750C + 273 K = 348 K n(H2) = 99191.84 0.0144 m3 / 8.314 348 K = 0.49 moles of H2 Pressure = 744 torr = 99191.84 Pa
Hydrogen is the limiting reagent, according to the calculation above.CH3OH = H2 = 0.49/2 = 0.245 m-238.6 (-110.5) = -128.1 kJ/mol for H(rxn) = H(f) (CH3OH) - H (rxn)
We must now multiply H(rxn) by the number of moles of methanol.
E = H(rxn) n(CH3OH) = 128.1 0.245 = 40.6 kJ.
Learn more about Ideal gas law here-
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Answer: Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Explanation:
- Firstly, we need to identify the reducing agent and the oxidizing agent.
- The reducing agent: is the agent that has been oxidized via losing electrons.
- The oxidizing agent: is the agent that has been reduced via gaining electrons.
- Here, Ti losses 4 electrons and its oxidation state is changed from 0 to +4 and Cl₂ gains one electron and its oxidation state is changed from 0 to -1.
- So, Ti is the reducing agent because its oxidation state changes from 0 to +4.
- Cl₂ is the oxidizing agent because its oxidation state changes from 0 to -1.
- Thus, The right answer is Ti is the reducing agent because it changes from 0 to +4 oxidation state.
Answer:
0.84kg of gatorade powder is needed.
Explanation:
From the question given above, we were told that the team manager mixes 0.6kg of gatorade powder with 5 gallons of water.
Now, to obtain the desired amount of the powder of gatorade needed for 7 gallons of water, we simply do the following:
If 0.6kg of gatorade powder required 5 gallons of water,
Then Xg of gatorade will require 7 gallons of water i.e
Xg of gatorade = (0.6 x 7)/5
Xg of gatorade = 0.84kg
Therefore, to maintain the same gatorade mixture, the team manager must mix 0.84kg of gatorade powder with the 7 gallons of water.
Convert 2430j to Kj that is divide by 1000
2430/1000=2.430
delta E =Q+W
q is the heat done
w is the work done and since is work is done is by the system therefore it is negative
w is therefore -5kj
q=-2.430
delta E =-2.430 + -5= -7.43kj/mol