Answer:
Hence the required dimension is 4cm.
Step-by-step explanation:
Given:
An Isosceles triangle with uneven side=l+1 cm
Area= 6 sq cm
To Find:
Height of Triangle.
Solution:
We know that area of triangle given by,
Area=1/2*base*height.
Here height =1+base
6=1/2((b+1)*b
12=(b+1)*b.
b^2+b-12=0
(b-3)(b+4)=0
b=3 or b=-4
So length never be negative
so b=3 cm
And height=b+1=3+1=4 cm.
Ok, logic
all of them are parabolas
1st and 3rd are opening up, so they defenitely increase, so no
decraseing
the vertex hs to be be at x=-4
y=a(x-h)^2+k
h has to be -4
y=a(x+4)^2+k
the answer is 2nd one or f(x)=-(x+4)^2+4
Answer:
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Step-by-step explanation:
