Answer:
12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.
Explanation:
For first solution of sulfuric acid :
C₁ = 40% , V₁ = ?
For second solution of sulfuric acid :
C₂ = 10% , V₂ = ?
For the resultant solution of sulfuric acid:
C₃ = 28% , V₃ = 20L
Also,
<u>V₁ + V₂ = V₃ = 20L</u> ......................................(1)
Using
<u>C₁V₁ + C₂V₂ = C₃V₃</u>
<u>40×V₁ + 10×V₂ = 28×20</u>
So,
40V₁ + 10V₂ = 560........................................(2)
Solving 1 and 2 as:
V₂ = 20 - V₁
Applying in 2
40V₁ + 10(20 - V₁) = 560
40V₁ + 200 - 10V₁ = 560
30V₁ = 360
<u>V₁ = 12 L</u>
So,
<u>V₂ = 20 - V₁ = 8L</u>
<u><em>12 L of 40% sulfuric acid solution and 8 L of 10% sulfuric acid solution are needed to make 20 L of sulfuric acid solution.</em></u>
Answer:
when atoms lose or gain electrons
Explanation:
From the periodic table you know that Cl has a molar mass of 35.35 g/m. So if you just set up the dimensional analysis as so: (.46 moles Cl)*(35.45 grams Cl/1 mole Cl) and multiply out you get 16 grams of Cl if you follow the sig figs and 16.307 if you don't.
Answer:
Less reactions because it does not have the best pH to for that particular enzyme to work in. If it was at pH of 7, ABC would work best and catalyze a lot of reactions, but since the pH is 9 it will not work as efficiently or better so it will catalyze less reactions.
Explanation:
1. Acid , H+ ion
2. Base , OH- ion
3. Base , OH- ion
4. Acid , H+ ion