The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
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There isnt one its has to be consistent but honestly idk
Answer:
2:25pm
Step-by-step explanation:
The time given is 5pm to catch the train back to school;
Amount of time for the tour = 1hr 45min
= 105min
Amount of time at gift shop = 30min
Amount of time to save = 20min
Total time = 105min + 30min + 20min = 155min
So;
Total time = 2hr 35min
So;
5pm - 2hr 35min = 2:25pm
64< 67< 125
64^ (1/3) < 67 ^ (1/3) < 125^ (1/3)
4 < 67^ (1/3) < 5
Choice 2