Adrian can put a total of 1716 combinations in the player.
The formula to be used is as follows:
total combinations = n!/[r! *(n-r)!]
n = number of disks available = 13
r = number of disks that be held = 6
= 13! = (13• 12•11•10•9•8•7•6•5•4•3•2•1)/(6! <span>• 7!)
</span>=1716
Thank you for posting your question. Feel free to ask me more.
7 dollars each game and I know that because 10 would be 60 plus 16 which is way over and 5 would be 25 plus 16 which is incorrect 6 would be 30 which adding 16 would be 46. FINALLY ADDING 5 extra which is 7 times which is 35 plus 16 is 51.
Hope this helped
:D
Dividing the number of successful outcomes by the number of possible outcomes is the definition of the probability of the given event.
P(E)=n(E)/n(S)
example. let the Experiment be throwing a dice. The sample space, all the possible outcomes, is the set S={1, 2, 3, 4, 5, 6 } and n(S)=6
Let the even E be: getting an even number. The successful outcomes set is E {2, 4, 6 } and n(E)=3
So probability of getting an even number is P(E)=n(E)/n(S)=3/6=0.5
Answer: Probability of the given Event
Answer:
90
Step-by-step explanation:
Multiple the number of all your options.
6 x 3 x 5 = 90