<h3>
Answer:</h3>
6.26 g C
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Given] 3.14 × 10²³ atoms C
[Solve] grams C
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of C - 12.01 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
6.26227 g C ≈ 6.26 g C
A and D
They are sometimes proven wrong and contradicted, so these would make the most sense
1.98 × 10^<span>-11</span><span> J i just took it this is the right awnser</span>
<span>Each mole contains Avagodro's number of atoms i.e. 6.023x10^23, so
3 moles x 6.023x10^23 atoms/mole = 18.069x10^23 atoms = 1.8x19^24 atoms </span>
Answer:
1-Mg+O2=reactants MgO-product
2-CaNr2+AlCl3=reactants CaCI2+AIBr3=product
3-C2H4+O2=reactants H2O+CO2=product
Explanation:
Reactants are on the left side and products on the right.