A light beam has speed c in vacuum and speed v in a certain plastic. The index of refraction n of this plastic is
1 answer:
Answer:
Explanation:
Refractive Index: It is a measure to find how fast the light travels through a medium. It is ration of the speed of light in vacuum to speed of light in the medium. Speed of light is not constant and varies depending on the density of the medium.
In vacuum the speed of light is 300000 km/s and is denoted by c. When the light beam enters any medium the speed will decrease. Here it is given that the speed in plastic is v. Thus the refractive index(n) is given as:
It is a dimensionless no.
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Answer:
a) a = 3.09 m/s²
b) aₓ = 2.60 m/s²
Explanation:
a) The magnitude of her acceleration can be calculated using the following equation:
<u>Where</u>:
: is the final speed = 8.89 m/s
: is the initial speed = 0 (since she starts from rest)
a: is the acceleration
d: is the distance = 12.8 m
Therefore, the magnitude of her acceleration is 3.09 m/s².
b) The component of her acceleration that is parallel to the ground is given by:
<u>Where</u>:
θ: is the angle respect to the ground = 32.6 °
Hence, the component of her acceleration that is parallel to the ground is 2.60 m/s².
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Answer:
<h3>The answer is 2 s</h3>Explanation:
The time of flight can be found by using the formula
d is the distance covered
v is the velocity
From the question we have
We have the final answer as
<h3>2 s</h3>Hope this helps you