The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
If your question looks like mine (shown in picture).Your answer would be number 4.
Hope this helps!
CTPehrson
Answer:
8 pounds of gummy bears.
Step-by-step explanation:
To find this answer I did:
40/30 = 4/3
Then,
4/3 x 6 = 24/3
This simplified is 8.
To check:
8/6 x 5 = 40/30
We can use the Pythagorean theorum
a^2+b^2=c^2
c^2 is the length of the longest side squared
so
6^2 + b^2 = 10^2
36+ b^2 = 100
-36 -36
b^2 = 64
b = 8
b is the same thing as your "x", so x = 8
Answer:
17.
Step-by-step explanation:
Statement: "ten more than the product of two and a number"
Translation: 10 + (2 * x)
x = 3.5
10 + (2 * 3.5)
= 10 + 7
= 17.
Hope this helps!
