Let x be the number of running plays
Y be the number of
passing plays
Since the total plays is 110
X + y = 110
And total yard is 378
3x + 7y = 378
Using the first equation
X = 110 – y and substitute to the 2nd equation
3(110 – y) + 7y = 378
And solve for y
Y = 12
Substitute to eqution 1
X = 110 – 12 = 98
Answer:
(The image is not provided, so i draw an idea of how i supposed that the problem is, the image is at the bottom)
Ok, we have a rectangle of length x by r.
At the extremes of length r, we add two semicircles.
So the perimeter will be equal to:
Two times x, plus the perimeter of the two semicircles (that can be thought as only one circle).
The radius of the semicircles is r, and the perimeter of a circle is:
C = 2*pi*r
where pi = 3.14
Then the perimeter of the track is:
P = 2*x + 2*pi*r.
b) now we want to solve this for x, this means isolating x in one side of the equation.
P - 2*pi*r = 2*x
P/2 - pi*r = x.
c) now we have:
P = 660ft
r = 50ft
then we can replace the values and find x.
x = 660ft/2 - 3.14*50ft = 173ft
Answer: Dealership 4: he would pay $40.33
Step-by-step explanation: I used a calculator, so if you have 1/3 you put 1 divided by 3 in your calculator and right that down somewhere completely
Then, you divide $121 dollars by the number you got for 1 divided by 3 and then multiply it by 121 and should get 40.3333333333 but you round to the nearest tenth so it would by 40.33
1÷3= 0.33333333333
121×0.33333333333= 40.3333333333