(x + 3)^2 + (x + 4)^2
= x^2 + 6x + 9 + x^2 + 8x + 16
= 2x^2 + 14x + 25
= 2(x^2 + 7x) + 25
= 2[(x + 7/2)^2 - 49/4] + 25
= 2(x + 7/2)^2 - 98/4 + 25
= 2(x + 7/2)^2 + 1/2
Its B
The domain is -3, -1, 0, 1, 5
Let's set up an equation.
so we know the answer is -13.
1/3 of a number (our variable) can be written as 1/3n.
8 less than that would be subtracting 1/3n by 8
so we have -13 = 1/3n - 8.
To solve:
Add 8 to both sides: -5 = 1/3n
Multiply both sides by 3 (to cancel fraction): -15 = n
You can check by plugging -15 into the equation we made.
Answer:
D
Step-by-step explanation:
Imagine this as a right angle triangle, where the diagonal length is the hypotenuse, the length is one side, and the width is the other.
We can therefore use Pythagoras' Theorem (or Pythagorean Theorem) to solve. The formula for this is a²+b²=c², where c is the hypotenuse, and a and b are the sides.
We can input the values we know to this formula to get the width. This gives 110²+b²=133.14² or 12100+b²=17 726.2596.
From there subtracting 12100 from both sides gives b²=5626.2596.
Square rooting b isolates it, leaving b=75.0083969.
Since the value of the diagonal was approximate, this can be assumed the b is 75m.
**This content involves Pythagoras' Theorem/Pythagorean Theorem, which you may wish to revise. I'm always happy to help!
Answer:
will you help me with grade 9 math, algebra 2 please
Step-by-step explanation:
