Answer:
i think the second question (the choose the Function) means choose the function that has changed the most.
the first choose function one, i dont know but... according to wikipedia, "an initial value problem is an ordinary differential equation together with an initial condition which specifies the value of the unknown function at a given point in the domain. Modeling a system in physics or other sciences frequently amounts to solving an initial value problem." hope this helps
Step-by-step explanation:
Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)² ↔ (y-k) = a(x-h)²
This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)
Latus rectum: y-value = 15/2
Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then
Latus rectum = 5
10089.67cm is your answer but dont trust m answer wait for other ones
Question 1
probability between 2.8 and 3.3
The graph of the normal distribution is shown in the diagram below. We first need to standardise the value of X=2.8 and value X=3.3. Standardising X is just another word for finding z-score
z-score for X = 2.8
(the negative answer shows the position of X = 2.8 on the left of mean which has z-score of 0)
z-score for X = 3.3
The probability of the value between z=-0.73 and z=0.49 is given by
P(Z<0.49) - P(Z<-0.73)
P(Z<0.49) = 0.9879
P(Z< -0.73) = 0.2327 (if you only have z-table that read to the left of positive value z, read the value of Z<0.73 then subtract answer from one)
A screenshot of z-table that allows reading of negative value is shown on the second diagram
P(Z<0.49) - P(Z<-0.73) = 0.9879 - 0.2327 = 0.7552 = 75.52%
Question 2
Probability between X=2.11 and X=3.5
z-score for X=2.11
z-score for X=3.5
the probability of P(Z<-2.41) < z < P(Z<0.98) is given by
P(Z<0.98) - P(Z<-2.41) = 0.8365 - 0.0080 = 0.8285 = 82.85%
Question 3
Probability less than X=2.96
z-score of X=2.96
P(Z<-0.34) = 0.3669 = 36.69%
Question 4
Probability more than X=3.4
P(Z>0.73) = 1 - P(Z<0.73) = 1-0.7673=0.2327 = 23.27%
For
y=a(x-h)^2+k
vertex is (h,k)
it could be
y=a(x+1)^2-3