All categories

3 years ago

A zoo has 2 male lions one sixth oh the lions are male lions how many lions are there at the zoo ?

1 answer:

7 0

It is important to go through details that are provided in the question. Based on those details the answer to the question can be easily deduced.
Let us assume the number of lions at the zoo = x
Number of male lions in the zoo = 2
Then
(1/6) * x = 2
x/6 = 2
x = 2 * 6
= 12
So there are a total of 12 lions in the zoo. I hope the procedure is clear enough for you to understand. Using this method, it will be possible for you to do similar problems in future without requiring any help from outside. Only be careful about the calculation part.

You might be interested in

A human body had 30 times as many platelets as white blood cells. A small sample of blood has 8×10'3 white blood cells. About ho

Contact [7]

To determine the number of platelets present in the human body, we need a relation that would relate this value to the given value above which is the number of white blood cells. Fortunately, we are given a ratio of 30. So, we use this value as follows:

number of platelets/number of white blood cells = 30
number of platelets / 8×10^3 white blood cells = 30
number of platelets = 240000

5 0

3 years ago

If the zeros of a quadratic functions are -2 and 4, which graph could represent the function?

anygoal [31]

Answer:

The Graph having the X-intercepts of (-2,0) and (4,0)

Step-by-step explanation:

The zeroes of the function is the X-intercept.

4 0

2 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

2 years ago

Find the area of the square with the side length of 2x+5

zimovet [89]

4x^2 +20x +25
(2x+5)(2x+5)

8 0

2 years ago

The diagram below shows a student using a clinometer to measure the height of a flagpole. When the student stands 40 feet away f

AVprozaik [17]

The correct answer is the flagpole is 33 feet high.

Explanation:
Please refer to the attached picture.

We know:
CD = 40 feet
AC = 5 feet
∠BDC = α = 35°

Using trigonometry, we know that the definition of the tangent of an angle is the ratio between the opposite side and the adjacent side, therefore:
tan α = BC / CD

Solving for BC:
BC = CD · tan α
= 40 · tan (35)
= 28 feet

In order to find the height of the flagpole, we need to add the distance of the clinometer from the ground:
AB = BC + AC
= 28 + 5
= 33

Hence, the flagpole is 33 feet high.

5 0

2 years ago