Answer:
Measure of exterior angle ABD = 136°
Step-by-step explanation:
Given:
measure of ∠A = (2x + 2)°
measure of ∠C = (x + 4)°
measure of ∠B = x°
Find:
Measure of exterior angle ABD
Computation:
Using angles sum property
∠A + ∠B + ∠C = 180°
So,
(2x + 2) + (x + 4) + x = 180
4x + 6 = 180
4x = 176
x = 44
So,
measure of ∠B = x°
measure of ∠B = 44°
Measure of exterior angle ABD = 180 - measure of ∠B
Measure of exterior angle ABD = 180 - 44
Measure of exterior angle ABD = 136°
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS = = 57.5°
Now, tan(57.5°) =
⇒ 1.5697 =
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) =
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = () × (ST)
= () × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²
Answer:
361.09
Step-by-step explanation:
Explanation:
Calculate the standard error of the mean, SE, using this formula, where is the standard deviation and n is the sample size.
For this situation, the sample size is 65, and the standard error of the mean is 44.8. Substitute these values into the formula, and solve for .
So the standard deviation is approximately 361.09.
Answer:
3.15 seconds is the answer.
<u>Explanation</u>
when the ball touches the ground, h =0
hence,
0=255-21t-16t²
16t²+21t-225=0
here a=16 ,b=21, c= -225
time cannot be negative, hence t = -4.46 can be avoided
The ball takes 3.15 seconds to hit the ground.