2 years ago

Solving system using elimination

Mathematics

1 answer:

Leto [7]2 years ago

7 0

(2,-3) is the answer

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4a/3-b/4=6 5a/6+b=13 Solve linear system by elimination

kondor19780726 [428]

$\bf \cfrac{4a}{3}-\cfrac{b}{4}=6
\qquad \qquad 
\cfrac{5a}{6}+b=13
\\\\\\
\textit{let us remove the denominators off those folks}\\
\textit{by multiplying the first one by 12, both sides}\\
\textit{and the second one by 6, both sides, thus}
\\\\\\
12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72
\\\\\\
6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78$

$\bf \textit{now, let's do the elimination}
\\\\

\begin{array}{llll}
16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\
5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\
&&--------\\
&&58a+0\quad=372
\end{array}$

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2 years ago

Complete the table for the given rule. rule: y=x-4 x:? y:6 0 4

Triss [41]

Answer:

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Step-by-step explanation:

10 - 4 = 6

4 - 4 = 0

8 - 4 = 4

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