1-1/6*3/2
multiply the two fractions
1/6*3/2
Cross out 3 and 6, divide by 3.
1/2 * 1/2
multiply the numerators together
1*1=1
multiply the denominators together
2*2=4
1-1/4
pretend that 1 has a denominator which is 1
1/1-1/4
find the common denominator for 1/1 which is 4
multiply by 4 for 1/1
1*4/1*4=4/4
4/4-1/4
Answer:
3/4
Answer:
c) at most 11.1%
Step-by-step explanation:
We have the data that is 97 ± 12, with 97 being the mean and 12 the standard deviation.
Now, the percentage of people who reached them for less than 73 dollars, if it were a normal distribution:
z = (73 - 97) / 12 = - 2
so it would be, a probability of 0.0228 or 0.228%.
But we don't know what distribution it has, but we can get an idea.
A and D discarded, as they are very high values, and 73 is well below the average.
B) is still a very high value.
Therefore the answer is C, at most 11.1%
Answer:
B. a = 4, b = -8, c = -3
Step-by-step explanation:
The quadratic equation given is:
The general form of a quadratic equation is given as:
Let us put the given equation in this form and then compare with the general form of the quadratic equation.
Therefore, by comparing:
a = 4
b = -8
c = -3
The correct option is B
Answer:
Yes, all equilateral triangles are acute.
Step-by-step explanation:
yea
hope this helps :)))
your answer would be x=21/13
When the logs have the same base: logb(f(x)) = logb(g(x)) --> f(x) g(x)
if im correct please mark brainliest :)
