Answer:
Equation of the circle (x-3)²+(y-5)²=(6.4)²
x² -6x +9 +y² -10y +25 = 40.96
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given endpoints of diameter P(−2, 1) and Q(8, 9)
Centre of circle = midpoint of diameter
Centre =
Centre (h, k) = (3 , 5)
<u><em>Step(ii):-</em></u>
The distance of two end points
PQ =
PQ = √164 = 12.8
Diameter d = 2r
radius r = d/2
Radius r = 6.4
<u><em>Final answer:-</em></u>
Equation of the circle
(x-h)²+(y-k)² = r²
(x-3)²+(y-5)²=(6.4)²
x² -6x +9 +y² -10y +25 = 40.96
x² -6x +y² -10y = 40.96-34
x² -6x +y² -10y -7= 0
Answer:
x+y = 112 ........ (1)
x-y = 62............ (2)
from (1) and (2)
2x = 174
x = 174/2
x = 87
sub x = 87 in (1)
x+y = 112
87+y = 112
y = 112 - 87
y = 25
so the numbers are 87 and 25
Step-by-step explanation:
Answer:
A. 1/2 (20 x 50) + 1/2 (20 x 10), 2 (1/2 x 20 x 50) + 2(1/2 x 20 x 10)
B. 100
Step-by-step explanation:
An = a1 + (n - 1)(d)
Where a1 is the first term and d is the common difference.
First find d, the common difference.
24, ____, 32
a3 a4 a5
Subtract 32-24 = 8
Subtract a5 - a3 = 2
Divide 8/2 = 4
d = 4
Use d and one of the values they give us to find a1.
a3 = 24
24 = a1 + (3 - 1)(4)
24 = a1 + 2(4)
24 = a1 + 8
Subtract 8 from both sides
16 = a1
an = 16 + (n - 1)(4)
Can also be written
an = 16 + 4n - 4
an = 4n + 12
Answer:
The area of the figure is equal to
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of the figure is equal to the area of a square plus the area of a triangle
<u>Find the area of the square</u>
The area of square is equal to
<u>Find the area of the triangle</u>
The area of the triangle is equal to
therefore
The area of the figure is equal to