Answer:
The equation you are asking for is
40*(t+3) = 55*t,
where t is the time counted after the second car started.
The equation says that the distance covered by each car from the starting point to the catching point is the same for both cars.
Step-by-step explanation:
Answer:
-I haven't done this, but I have copied and pasted from another question and answer from the user syed514:
Graphing is one way to do the problem.But sometimes, graphing it is hard to do.So here’s an algebraic method.
If M(m1, m2) is the midpoint of two points A(x1, y1) and B(x2, y2),then m1 = (x1 + x2)/2 and m2 = (y1 + y2)/2.In other words, the x-coordinate of the midpointis the average of the x-coordinates of the two points,and the y-coordinate of the midpointis the average of the y-coordinates of the two points.
Let B have coordinates (x2, y2) in our problem.Then we have that 6 = (2 + x2)/2 and 8 = (3 + y2)/2.
Solving for the coordinates gives x2 = 10, y2 = 13
Answer: A: I'm pretty sure
Step-by-step explanation: if you look at the graph the the 2 and 16 are the only lines where the 0 runs across and its also where the ticket prices are.
Answer:
In lakhs I guess I don't know
5x - 3y = 15
5x - <u>5x</u> -3y = <u>- 5x</u> + 15
<u>-3y</u> = <u>-5x</u> + 15
3y = 5x - 15
divide all of them by 3...
y = 5/3 - 5
