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2 years ago

I have a 3 foot board that needs to be equally decided into 1/2 how many extra peices will I have

Mathematics

1 answer:

anygoal [31]2 years ago

7 0

Answer:

No extra pieces.

Step-by-step explanation:

Given:

Total number of foot board = 3

Equally divided into = 1/2

Question asked:

How many extra pieces will I have = ?

Solution:

By dividing 3 by 1/2 we can find the extra pieces.

= $3\div\frac{1}{2}$

= $3\times\frac{2}{1}$

= $6$

Since, the remainder is zero, thus there is no any extra pieces I have.

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What is the equation of a line that is parallel to y=47x−3 and passes through (14, 4)?

Shtirlitz [24]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where

m = slope

c = intercept

The equation of the given line is

y = 47x - 3

Comparing with the slope intercept equation, m = 47

If two lines are parallel, it means that they have equal slope. This means that the slope of the line passing through (14, 4) is 47

We would determine the intercept, c by substituting m= 47, x = 14 and y = 4 into y = mx + c. It becomes

4 = 47× 14 + c

4 = 658 + c

c = 4 - 658 = - 654

The equation becomes

y = 47x - 654

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2 years ago

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Tamiku [17]

I hope this helps you

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3 years ago

Which expression has the same value as 4x – 3y?

coldgirl [10]

Answer:

4x+(-3y)

Step-by-step explanation:

$\\ \rm\longmapsto 4x+(-3y)$

(-)(-)=(+)
(+)(-)=(-)
(-)(+)=(-)
(+)(+)=(+)

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2 years ago

Determine whether the following sequence is arithmetic, geometric, or neither.

harkovskaia [24]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

2 years ago