Answer:
a) 0.432, b) 0.1029 and c) 0.08
Step-by-step explanation:
a) what is the probability that you get 2 chocolate-flavor donuts and one vanilla-flavor donut?
Observe that there are 3 possible ways for this to happen. Getting a vanilla donut first, second or third. And every of this cases has a probability of
Therefore, the probability of a) to happen is given by:
b) What is the probability that he gets 5 chocolate-flavor donuts?
Observe that:
- There are ways to choose 5 chocolate donuts between 10
- The probability of each one of those cases to happen is given by
Therefore the probability of b) to happen is given by:
c) what is the probability that he eats 10 donuts that day?
Observe that, in order for the donut lover to eat exactly 10 donuts 2 things must happen
- He should have eaten 9 donuts from which 3 of them were chocolate-flavored.
- The 10th donut he ates must be a chocolate-flavored one.
Then we proceed to compute the probability of 1 the same way as in b).
- There are ways to choose 3 chocolate donuts between 9
- The probability of each one of those cases to happen is given by
Therefore the probability of 1 to happen is given by:
Finally the probability of 2 to happen is known to be 0.3 and, as 1 and 2 are independent events, the probability of both to happen is the multiplication of the probabilities. Then, the answer for c) is: