Is that a trick question wouldn't it be 20??? I'm confused
Adding the equations to eliminate p would be the correct step because when you add the equations together, the variable p would cancel out and be eliminated leaving you with 2w=35 you can then solve for the value of w which you can then input to find the value of p, allowing you to solve for the values of both p and w.
Probabblity that the cube lands on 4 = 1/6
Probablity that the coin lands heads up = 1/2
Probablity of both happening = 1/2 * 1/6 = 1/12
Well 5/6 x 3/4 is 15/24 so you’d do 24 dots across in 15 rows