The first mechanic worked for 10 hours and the second mechanic worked for 15 hours.
Step-by-step explanation:
Given,
Charges of first mechanic = $95 per hour
Charges of second mechanic = $115 per hour
Total hours = 25
Total amount charged = $2675
Let,
The number of hours worked by first mechanic = x
The number of hours worked by second mechanic = y
According to given statement;
x+y=25 Eqn 1
95x+115y=2675 Eqn 2
Multiplying Eqn 1 by 95
Subtracting Eqn 3 from Eqn 2
Dividing both sides by 20
Putting y=15 in Eqn 1
The first mechanic worked for 10 hours and the second mechanic worked for 15 hours.
Keywords: linear equation, elimination method
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Answer:
10:7
Step-by-step explanation:
40:28 are both divisible by 4. 40/4 is 10. 28/4 is 7. So the ratio would be 10:7 since neither is divisible by both the same number, this is the final ratio.
Answer:
Step-by-step explanation:
Let the number of hours Nick does the job alone to be x - 3 hours
Hence, in 1 hour, Nick has done 1/x - 3
Together they complete the job in 9 hours
Hence, let's represent the job as 1
9/x + 9/x - 3 = 1
Multiply through by (x)(x-3)
9(x- 3) + 9(x) = 1
9x - 27 + 9x = (x)(x-3)
-27 = x² - 3x
x² - 3x +27 = 0
Answer:
Step-by-step explanation:
eq. of any line withslope 1/6 is
y=1/6x+c
∵ it passes through (-2,7)
so 7=1/6(-2)+c
c=7+1/3=22/3
eq. of line is
y=1/6x+22/3