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2 years ago

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Math problem: electrical polls that carry electrical wire seem.to get smaller the farther away they are from you. find the appar

ent height of each if the tallest polls 50 ft ft and the distance between each is 100ft

1 answer:

vivado [14]2 years ago

7 0

Mayonnaise is an instrument

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Compare the numerical expressions.

lord [1]

Answer + Step-by-step explanation:

<u>24 + 7 and 9×(24+7)</u>

31 and 9 x (31)

31 and 279

the number is multiplied by 9

<u>12 - 7 and 4x(12-7)</u>

5 and 4 x (5)

5 and 20

the number is multiplied by 4

<u>3×(21 + 4) and 21 + 4</u>

3 x (25) and 25

75 and 25

the number is multiplied by 3

making the left side 3 times larger

<u>40 × 5 and 40 × 20</u>

200 and 800

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1 year ago

Marcus baked a loaf of banana bread for a party. He cut the loaf into equal size pieces.how can you find the number of pieces in

Oliga [24]

If he cut the loaf into equal pieces, then told you 1/3 was left you could check the even multiples of three. Such as six. So he could have 2 pieces left of his loaf if he cut them into six pieces because 1/3 = 2/6

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2 years ago

Which relationship describes angles 1 and 2?

vaieri [72.5K]

Answer:

do u got a picture by chance

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Roman55 [17]

Answer:

2.53×10^8 liters

Step-by-step explanation:

(8.65×10^3 L/da)(0.292×10^5 da) ≈ 2.53×10^8 L

3 0

2 years ago

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h

creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

$V = x^2h cm^3$

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

$V = 2xh(dx/dt)+ x^2(dh/dt)$

Substituting the given values , we will get

$[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)$ [/tex]

$dV/dt = -288+144 = -144cm^3/min$

So at that moment, the volume is decreasing at the rate of

$144 cm^3/min$

4 0

2 years ago

Read 2 more answers