m = mass of the ice added = ?
M = mass of water = 1.90 kg
= specific heat of the water = 4186 J/(kg ⁰C)
= specific heat of the ice = 2000 J/(kg ⁰C)
= latent heat of fusion of ice to water = 3.35 x 10⁵ J/kg
= initial temperature of ice = 0 ⁰C
= initial temperature of water = 79 ⁰C
T = final equilibrium temperature = 8 ⁰C
using conservation of heat
Heat gained by ice = Heat lost by water
m (T - ) + m = M ( - T)
inserting the values
m (4186) (8 - 0) + m (3.35 x 10⁵ ) = (1.90) (4186) (79 - 8)
m = 1.53 kg
Chemical energy holds molecules together by forming the bonds between atoms. the form of electric bonds.
Resitance (R)= 10 Ohm
Potential difference (V) = 9V
V= IR
I= V/R
I= 9/10
I= 0.9 Ampere
Therefore 0.9 Ampere of current is flowing through the circuit.
Each point in the chain supports the weight of all the mass below it.
At the bottom end of the chain, the weight is (175 x 9.8) = 1,715 N .
At the top of the chain, the weight is (175 + 12) x (9.8) = 1,833 N .
The tension in the chain varies linearly from 1,715N at the bottom
to 1,833N at the top.
<span>273 K is the freezing point of water and it is equal to 0 degrees Celcius ,In this change ,heat is released so as to gain the suitable temperature for freezing.273 K is just the Celsius scale but with being 0 but the same scale ,this number was arrived at because temperature comes from the motion of a substance's particles.</span>
