Answer:
The probability you will get a head at least once is 50%.
Step-by-step explanation:
Since the question is asking about the probability you will get, we can assume we’re answering based on theoretical probability. This type of probability is based on logic.
A coin always has two sides, one with head and the other with tails. So we can easily represent this as half and half. 1/2 as a fraction. 0.5 as a decimal. 50% as a percent. This means that P(H) will be equal to any one of these as they are all the same. The same can be said for the probability that a head does not appear, in other words, a tail appears. The reason being that the probability is split evenly between the two. This will again mean that P(T) will equal to any one of those.
So, A = 50% and B = 50%. The probability you will get a head at least once is 50%.
There are 430 non square numbers that lie between 
and 
.
Given two numbers and and we are require to find non square numbers that lie between them.
Numbers can be consecutive numbers or non consecutive numbers. In our question we will find the consecutive numbers.
Square numbers are those numbers whos square is in a proper number means decimal should not be there.
First number=
Second number=
First we have to find the exact value of numbers by finding the square of these numbers.
First number=215*215=46225
Second number=216*216=46656
Numbers that lie between them=(46656-46225)-1
=431-1
=430
Hence 430 numbers lie between and .
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Answer: The first card is a diamond and the second card is a heart. Both cards are hearts. Let H denote the event that a heart is drawn; let D denote the event that a diamond is drawn. The first card is a diamond and the second card is a heart: The probability of drawing a diamond on the first draw
Step-by-step explanation:
a > b
A . a^5b^3/ab^4 = a^4/b
B. a^4 / a*a*a*a = a^4 / a^4 = 1
C. ab^2 / a^2b = b/a
D. b*b*b/b^3 = b^3/b^3 = 1
B and D, doesn't matter what values of a and b it's always equal 1
Lets say a = 2 and b = 1
A. a^4/b = 2^4 / 1 = 16/1 = 16
C. b/a = 1/2 = 0.5
So C has the least value
Answer:
ab^2 / a^2b
Answer:
2 / 13
Step-by-step explanation:
Number of cards in a standard deck = 52
Number of 4's = 4 ( 1 for each suit)
Number of 6's = 4 (1 for each suit)
Probability, P = required outcome / Total possible outcomes
P(a 4) = 4 / 52 = 1/ 13
P(a 6) = 4 /52 = 1/13
Probability of either a 4 or a 6
P(a 4) + P(a 6)
1/13 + 1/13
= 2 / 13
