A car with a velocity of 22 m/s is accelerated at a rate of 1.6 
for 6.8s has the final velocity t be 32.88 m/s.
The acceleration means the amount of velocity changing per unit time.
The given data:
initial velocity, u = 22 m/s
time, t = 6.8 s
acceleration, a = 1.6
We will be using the equation of motion:
v = u + at
The final velocity become 32.88 m/s.
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The answer would be E7. Galaxies categorized as E0 look to
be nearly perfect, while those registered as E7 seem much extended than they
are widespread. It is worth noting, though, that a galaxy's look is connected
to how it lies on the sky when viewed from Earth. An E7 galaxy is very long and
thin or the flattest of them all.
Explanation:
We have,
Surface area, 
The current varies wrt time t as :
(a) At t = 2 seconds, electrical charge is given by :
(b) Current is given by :
Instantaneous current at t = 1 s is,
(c) Current is, 
Current density is given by electric current per unit area.
Therefore, it is the required explanation.
Answer:
potential energy PE = M g h
KE at bottom = 1/2 M V^2
Regardless of the slope of the slide the change in energy is the same
1/2 V^2 = g h
V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s
Perhaps the question says that h = 55 * .1 = 5.5 m
Then V = (2 * 9.8 * 5.5) = 10.4 m/s
Answer:
m1=100kg
m2=6×10^24kg
r=6400km
G=6.6×10^-11
F=?
as we know that
F=G m1.m2/r²
F=6.6×10^-11×100×6×10^24/(6400)²
F=6.6×10^-11×6×10^26/4.096×10^7
F=6.6×10^-11×1.465×10^19
F=9.67×10^8N
