A figure formed by 3 segments connecting 3 non-colinear points
Answer:
A score of 117 is needed, which Is not possible since the test is over 100.
Step-by-step explanation:
The other 3 scores are 85, 94,84 . Let's x be the 4th score he must score.
Therefore ( 85 + 94 + 84 + X)/4 =95
Then 263+X /4 =95
Cross mutiplying 4*95=263+X
Therefore X= 380-263
X= 117 which is not possible since the test score is over 100.
The answer is B). graph B
Polar coordinates=<span>(6sqrt 2, 3pi/4)=(r, theta)→r=6 sqrt 2, theta=3pi/4
Rectangular coordinates=(x,y)=?
x=r cos theta=(6 sqrt 2) cos(3pi/4)=(6 sqrt 2)(-sqrt 2 / 2)
x=-3 (sqrt 2)^2=-3(2)→x=-6
y=r sin theta=(6 sqrt 2) sin (3pi/4)=(6 sqrt 2)(sqrt 2 / 2)
y=3 (sqrt 2)^2=3(2)→y=6
Rectangular coordinates of the point = (x,y) =(-6,6)
Answer: Option a. (-6,6) </span>
