Answer:
-2
Step-by-step explanation:
since the parabola opens upwards, the minimum is at the vertex of the parabola and the maximum is infinity, because the lines of a parabola goes on forever
you look for the smallest x value for the parabola and since you can see that the vertex of the parabola lies on x=-2, the minimum value of the function is -2.
Hope that helps :)
f(x)=x²-1
g(x)=2x-3
f(x)*g(x)=(x²-1)*(2x-3)-----------> <span>this function exists for all real numbers</span>
the answer is the interval (-∞,∞)
using a graph tool see the attached figure
The given statement is false.
What is the effect of a row operation on a determinant?
The factor by which a row operation intends to change the determinant is not equal to the determinant of the elementary matrix corresponding to that row operation. Rather, when a row is scaled up by a factor in a matrix, the determinant of that matrix also scales up by that factor.
Similarly, the factor by which a row operation changes the determinant is equal to the factor times the determinant of the elementary matrix corresponding to that row operation.
Learn more about a matrix here:
brainly.com/question/9967572
#SPJ4
Step-by-step explanation:
f(x) + n - move the graph n units up
f(x) - n - move the graph n units down
f(x + n) - move the graph n units to the left
f(x - n) - move the graph n units to the right
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We have f(x) = 2ˣ.
g(x) = f(x) + 1 - move the graph of f(x) one unit up.
<em>(look at the picture)</em>
