Answer:
C
Step-by-step explanation:
In the left/right direction, your circle (at it's biggest point) goes from -5 to 5
the middle of -5 and 5 is 0
so the center of your circle should have a x = 0
in the (x , y) point
the only option that has
(0, something)
is C
Therefore your answer is C
Answer:
$1003.84615
Step-by-step explanation:
130.5 = x * 0.13
130.5/0.13 = x
x = 1003.84615
7/5 = 14/10 = 28/20
Numerator = x
Denominator = x-4
Add 3 to both:
x +3 / (x-4+3)
x+3 = 14
(x-4 +3) = 10 = x-1 = 10
x = 11
Check:
11 -4 = 7 ( denominator is 4 less than the numerator.)
add 3 to both:
11+3 = 14
7+3 = 10
14/10 reduces to 7/5
The original fraction would be 11/7
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.