Answer:
Answer:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Where xx is the number of small boxes sent and yy is the number of large boxes sent.
Step-by-step explanation:
Let be xx the number of small boxes sent and yy the number of large boxes sent.
Since each small box can hold 20 books (20x20x ), each large box can hold 30 books (30y30y )and altogether can hold a total of 280 books, we can write the following equation to represent this:
20x+30y=28020x+30y=280
According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:
y=4xy=4x
Therefore, the system of equation that be used to determine the number of small boxes sent and the number of large boxes sent, is:
\{ {{20x+30y=280} \atop {y=4x}} .{
y=4x
20x+30y=280
.
Answer:
r= C over 2π
Step-by-step explanation:
C = 2πr
To solve for r, divide each side by 2π
C/ 2π = 2πr/ 2π
C/ 2π = r
1.09 because all percents are divided by 100 to find the decimal
Answer:
1. Yes
2. They could change the 60° angle into a different one.
Step-by-step explanation:
1. Two triangles are the same if they share two side lengths with the same angle between them.
2. Since the triangles are equal if they share two side lengths with the same angle between them, if they changed the angle between 3 and 5, it'd no longer be the same triangle.
