When put in matrix form, the coefficients of
... 3x -2y = 7
... x + 4y = 2
look like
The determinant is 3×4 - 1×(-2) = 14.
Let's solve your equation step-by-step.
2(3x−1)=−6x−2
Step 1: Simplify both sides of the equation.
2(3x−1)=−6x−2
(2)(3x)+(2)(−1)=−6x+−2(Distribute)
6x+−2=−6x+−2
6x−2=−6x−2
Step 2: Add 6x to both sides.
6x−2+6x=−6x−2+6x
12x−2=−2
Step 3: Add 2 to both sides.
12x−2+2=−2+2
12x=0
Step 4: Divide both sides by 12.
12x/12= 0/12
x=0
Answer:
x=0
HOPE THIS HELPS!!! :)
Answer:
Step-by-step explanation:
we know that
The formula to calculate the coordinates of the midpoint between two points is equal to
we have that
The coordinates of diagonal WY are
substitute in the formula to calculate the midpoint
Answer:
1. ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y)
2. ∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)
Step-by-step explanation:
If we negate a quantified statement, first we negate all the quantifiers in the statement from left to right, ( keeping the same order ) then we negative the statement,
Here, the given statement,
1. ∃y ∈Z such that ∀x ∈Z, R (x + y)
By the above definition,
Negation of this statement is ∀ y ∈ Z such that ∃ x ∈ Z, ¬R (x + y),
2. Similarly,
The negation of statement ∀x ∈Z, ∃y∈Z such that R(x + y),
∃ x ∈ Z, ∀ y ∈ Z such that ¬R(x + y)