10x+2x+13=145
angle of WIJ and HIW is equal to 145 degrees
12x+13=145
12x=132
x=11
angle of WIJ is 10x
angle of HIW is 2x+13
to find angle of HIW, you plug in x=11 into 2x+13 and
the answer and angle of HIW is 35 degrees.
1 over 3 should be the answer I think
Answer:
2a(b^3 - 7b + 8)
Step-by-step explanation:
I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.
Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.
2a2b3 - 14ab + 16a
2(ab^3 - 7ab +8a)
2a(b^3 - 7b + 8)
<h3>
Answer:</h3>
c) 7π cm
<h3>
Step-by-step explanation:</h3>
The length of an arc (s) is related to its central angle (θ) and the radius of the circle (r) by ...
... s = rθ . . . . . . . . . θ in radians
Here, the central angle measures are given in "grads". There are 400 grads in a circle, so 200 grads in π radians. To convert grads to radians, we multiply the number of grads by π/(200g).
Then the lengths of the arcs are ...
... arc AB = (20 cm)·(50g·(π/(200g))) = 5π cm
... arc BC = (10 cm)·(40g·(π/(200g))) = 2π cm
E = arc AB + arc BC = 5π cm + 2π cm = 7π cm