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3 years ago

8

What type of climate would be near cold ocean currents? PLEASE HELP QUICK!!

1 answer:

olya-2409 [2.1K]3 years ago

5 0

Answer:

hot humid with lots of rain.

Explanation:

ocean currents act as conveyer belts of warm and cold water sending heat to the polar regions and helping the tropical areas cool off, thus influencing both weather and climate. the tropics are particularly rainy because heat absorption , and thus ocean evaporation, is highest.

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At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet

expeople1 [14]

As we know that KE and PE is same at a given position

so we will have as a function of position given as

$KE = \frac{1}{2}m\omega^2(A^2 - x^2)$

also the PE is given as function of position as

$PE = \frac{1}{2}m\omega^2x^2$

now it is given that

KE = PE

now we will have

$\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2$

$A^2 - x^2 = x^2$

$2x^2 = A^2$

$x = \frac{A}{\sqrt2}$

so the position is 0.707 times of amplitude when KE and PE will be same

Part b)

KE of SHO at x = A/3

we can use the formula

$KE = \frac{1}{2}m\omega^2(A^2 - x^2)$

now to find the fraction of kinetic energy

$f = \frac{KE}{TE} = \frac{A^2 - x^2}{A^2}$

$f = \frac{A^2 - (\frac{A}{3})^2}{A^2}$

$f_k = \frac{8}{9}$

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

$f_{PE} = 1 - f_k$

$f_{PE} = 1 - (8/9) = 1/9$

7 0

2 years ago

An aircraft travels a distance of 50km in a straight line

Juliette [100K]

Answer:

200 m/s

Explanation:

v = distance / time = 50km/250s = 50000m/250s = 200 m/s

6 0

1 year ago

A(n) 1946 kg car travels at a speed of 10 m/s . What is its kinetic energy ? Answer in units of J.

erica [24]

Answer:

KE=97300J

Explanation:

KE=1/2mv^2

KE=1/2(1946)(10)^2

KE=97300J

4 0

2 years ago

Kyle has the mass of 54 kg and is jogging at a velocity of m/s. What is Kyle’s kinetic energy

inysia [295]

m = mass = 54 kg

v = velocity = 3 m/s

KE = (1/2)*m*v^2

KE = (1/2) * 54 * (3)^2

KE = 243 J

Hope this helps!

3 0

2 years ago

Read 2 more answers

Select the correct answer

Rasek [7]

Answer:

I would say the net force acting on the car is in the opposite direction of the car's motion is correct

5 0

2 years ago

Read 2 more answers