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2 years ago

11

B) How much mg can the child receive per dose? A: 531.82 mg

1 answer:

mars1129 [50]2 years ago

4 0

A.) 531.82
There's no other answer choices so-

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Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

2 years ago

Please help me with the problems circled in green thank you in advance

Zigmanuir [339]

1) 6yds 2)2000mL 3)10.46km 4)10560ft 8)6300 meters

6 0

2 years ago

Read 2 more answers

F(x) = -2x, x<2<br> x2 - 4x + 1, x>2<br> 4

Sidana [21]

Answer:

Step-by-step explanation:

..

4 0

2 years ago

Read 2 more answers

FInding the length of EB

larisa86 [58]

Answer:

EB=3.3

Step-by-step explanation:

From the diagram, triangle ABC is similar to triangle DBE.

This means that, the corresponding sides are proportional.

It was given that AC=6, DE=4, CB=5.

We want to find EB=x

Since the ratio of corresponding sides are proportional, we have:

$\frac{EB}{CB} =\frac{ED}{AC}$

We substitute to obtain:

$\frac{x}{5} =\frac{4}{6}$

Multiply both sides by 5 to get:

$x=\frac{4}{6}\times 5=\frac{20}{6}=\frac{10}{3}=3.3$

4 0

2 years ago

Write an equation in standard form if the line that passes through (7,-3) and had a slope if 4

zvonat [6]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$\bf (\stackrel{x_1}{7}~,~\stackrel{y_1}{-3})~\hspace{10em} \stackrel{slope}{m}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{4}(x-\stackrel{x_1}{7})\implies y+3=4x-28 \\\\\\ y=4x-31\implies -4x+y=-31\implies 4x-y=31$

8 0

2 years ago