Pythagorean thoerem
we imagine the wall as a leg of a right triangle, the ladder is the hypotonuse and the distance from the bottom of the ladder to the wall is the other leg
so if we have a right triangle with leg length a and b and hypotnuse length c then
a²+b²=c²
so
given that one of the legs is 9ft (9 ft is the height of the triangle)
and the hypotnuse is 12 ft (length of ladder)
then say the last leg is x
so
x²+9²=12²
x²+81=144
mius 81 both sides
x²=63
sqrt both sides
x=√63
x=3√7
you should place it 3√7ft or about 7.9 or 8ft away
Answer:
I do not know if that x is a multiply sign or a variable so I'm going to answer both
If the x is a multiplication sign then the answer is -20 = -9
If the x is a variable then the answer is x = -2
Step-by-step explanation:
1/2(5 * -8) = -9
(1 * 5 * -8)/2 = -9
(5 * -8)/2 = -9
-40/2 = -9
-20 = -9
-20 ≠ -9
1/2(5x - 8) = -9
1(5x -8)/2 = -9
(5x - 8)/2 = -9
2((5x - 8)/2) = -9 * 2
2(5x - 8)/2 = -9 * 2
5x - 8 = -9 * 2
5x - 8 = -18
+8 +8
------------------
5x = -10
x = -10/5
x = -2
Check the picture below.
make sure your calculator is in Degree mode.
One approach that might be a great help would be if you would look
at the choices ... those things at the bottom of the question that you
didn't give us.
-- One leg is 3 times the length of the other leg.
-- Any right triangle that has one leg three times as long as the other
leg is similar to this triangle.
I'll bet that if you look through the choices, you'll find one there.