Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Answer:
3/4
Step-by-step explanation:
3/4 as a decimal is .75
.75>.73
Answer:
40cm^2
Step-by-step explanation:
A=a+b/2×h
A=6+10/2*5
A=16cm/2*5cm
A=8cm*5cm
A=40cm^2
Triangularizing matrix gives the matrix that has only zeroes above or below the main diagonal. To find which option is correct we need to calculate all of them.
In all these options we calculate result and write it into row that is first mentioned:
A)R1-R3
B)2R2-R3
C)-2R1+R3
D)2R1+R3
E)3R1+R3
None of the options will triangularize this matrix. The only way to <span>triangularize this matrix is
R3-2R1
</span>
<span>
This equation is similar to C) but in reverse order. Order in which rows are written is important.</span>