<span>Answer:
sin(incidence)/sin(refraction) = n_refraction/n_incidence
sin(50) / sin(x) = 1.5 / 1
sin(50)/1.5 = sin(x)
sin(x) = 0.511
x = 30.71o
B]
50 degrees, same as the angle going in.
You can show that by reversing the steps in A.
sin(30.7)/sin(x) = 1/1.5
C]
The glass is 5 cm thick.
The reference angle = 30.7o
Tan(30.7) = displacement / thickness
Tan(30.7) = x / 5
5*sin(30.7) = x
x = 2.97 cm which is the displacement.</span>
Answer:
A) 31 kJ
B) 1.92 KJ
C) 40 , 2.48
Explanation:
weight of person ( m ) = 79 kg
height of jump ( h ) = 0.510 m
Compression of joint material ( d ) = 1.30 cm ≈ 0.013 m
A) calculate the force
Fd = mgh
F = mgh / d
W = mg
F(net) = W + F = mg ( 1 +
= 79 * 9.81 ( 1 + (0.51 / 0.013) )
= 774.99 ( 40.231 ) ≈ 31 KJ
B) calculate the force when the stopping distance = 0.345 m
d = 0.345 m
Fd = mgh hence F = mgh / d
F(net) = W + F = mg ( 1 +
= 79 * 9.81 ( 1 + (0.51 / 0.345) )
= 774.99 ( 2.478 ) = 1.92 KJ
C) Ratio of force in part a with weight of person
= 31000 / ( 79 * 9.81 ) = 31000 / 774.99 = 40
Ratio of force in part b with weight of person
= 1920 / 774.99 = 2.48
"Wheel & Axle" <span>can be described as a shaft that is attached to the center of a wheel
Hope this helps!</span>