Answer:
width = w
length= 3w+1
perimeter= 5(3w+1) -45
perimeter = 2(l+b)
5(3w+1) -45 = 2{(3w+1)+w}
15w - 40 = 8w+2
6w = 42
w =7
therefore width = <u>7</u>
length= 3w+1 = <u>22</u>
perimeter= <u>65</u>
Step-by-step explanation:
<h2>
Hello!</h2>
The answer is:
The area of the rhombus is equal to 64 squared inches.
<h2>
Why?</h2>
Since we already know half of the length of the diagonals of the rhombus, we can calculate the area of the rhombus using the following formula:
From the image we can see that:
So, substituting, we have:
Hence, we have that the area of the rhombus is equal to 64 square inches.
Have a nice day!
Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
The first answer
-40y3/x5