Answer: PAY ATTENTION IN CLASS AND STOP TALKING TO YOUR FRIENDS
Step-by-step explanation:
If (x+5) is a factor the equation will equal zero when x=-5 so
3(-5^2)+14(-5)+k=0
75-70+k=0
5+k=0
k=-5
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44