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2 years ago

10

The goat population on a farm is decreasing at a rate of 7.25% each year. If there were 75 goats originally, how many goats will

be on the farm in 4 years?

1 answer:

Natasha2012 [34]2 years ago

3 0

Answer:

53

Step-by-step explanation:

x/75=7.25/100

Cross Multiply

100x = 543.75

Simplify

x=5.4375

Multiply By The Number Of Years

5.4375 x 4 = 21.75

Subtract From The Original Number

75-21.75 = 53.25

<h2>Round it down (You cant have a quarter o a sheep. It would be dead)</h2><h2>53</h2>

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3/8(2x-8/3x)=21 solve the equation for x

mart [117]

Answer:

$\boxed{\bold{x=-84}}$

Explanation:

Multiply Both Sides By 8:

= $\bold{8\cdot \frac{3}{8}\left(2x-\frac{8}{3}x\right)=21\cdot \:8}$

Simplify:

= $\bold{-2x=168}$

Divide Both Sides By -2:

= $\bold{\frac{-2x}{-2}=\frac{168}{-2}}$

Simplify:

= $\bold{x=-84}$

//Mordancy //.

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2 years ago

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Determine the length of the leg of 45°- 45°- 90° triangle with a hypotenuse length of 38.

Mashutka [201]

Answer:Hello! Hopefully your question is.......

19√2

Step-by-step explanation:

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3 0

2 years ago

I am having trouble understanding this: Sam bought 86 pounds of flour for his bakery. Every day he used the same amount of flour

oksano4ka [1.4K]

Answer:

the average amount of flour used each day=6.08 pounds

Step-by-step explanation:

Sam bought 86 pounds of flour for his bakery.

Every day he used the same amount of flour to make bakery items.

After 10 days, Sam was left with 25.2 pounds of flour.

Now we are asked to find the average pounds of flour that Sam used each day.

Total amount of flour used=86-25.2=60.8 pounds.

As he used the flour equal amount each day for 10 days.

So, the average flour used each day=

amount of flour used/ number of days=60.8/10=6.08.

the average amount of flour used each day=6.08 pounds

8 0

2 years ago

Read 2 more answers

Will mark as brainlist

lara [203]

Step-by-step explanation:

Tn=ar^(n-1)

r=-10/-5=2

a=-5

Tn=-5×(2)^(n-1)

Tn=-5•(2)^(n-1)

an=5•(2)^(n-1)

7 0

1 year ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago