(a) The speed of a satellite on a low lying circular orbit around this planet is 7,338.93 m/s.
(b) The minimum speed required for a satellite in order to break free permanently from the planet is 10,378.82 m/s.
(c) The radius of the synchronous orbit of a satellite is 69,801 km .
<h3>Speed of the satellite</h3>
v = √GM/r
where;
- M is mass of the planet
- r is radius of the planet
v = √[(6.67 x 10⁻¹¹ x 4.74 x 10²⁴) / (5870 x 10³)]
v = 7,338.93 m/s
<h3>Escape velocity of the satellite</h3>
v = √2GM/r
v = √[( 2 x 6.67 x 10⁻¹¹ x 4.74 x 10²⁴) / (5870 x 10³)]
v = 10,378.82 m/s
<h3>Speed of the satellite at the given period </h3>
v = 2πr/T
r = vT/2π
r = (7,338.93 x 16.6 x 3600 s) / (2π)
r = 69,801 km
Thus, the speed of a satellite on a low lying circular orbit around this planet is 7,338.93 m/s.
The minimum speed required for a satellite in order to break free permanently from the planet is 10,378.82 m/s.
The radius of the synchronous orbit of a satellite is 69,801 km .
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Food in a microwave oven heats itself by absorbing
radiation in the form of radio-waves.
the color violet has the shortest wavelength!
(a) The initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.
(b) The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.
<h3>
Initial vertical velocity</h3>
The initial vertical velocity of the stone is calculated as follows;
Vi = Vsinθ
Vi = 22 x sin(50)
Vi = 16.85 m/s
<h3>Initial horizontal velocity</h3>
Vxi = V cosθ
Vxi = 22 x cos(50)
Vxi = 14.14 m/s
<h3>Final vertical velocity of the stone</h3>
Vf = Vi - gt
where;
- Vf is the final vertical velocity = 0 at maximum height
<h3 /><h3>Final horizontal velocity of the stone</h3>
Vfx = Vxi = 14.14 m/s
Thus, the initial vertical velocity of the stone is 16.85 m/s and the initial horizontal velocity is 14.14 m/s.
The final vertical velocity is 0 and the final horizontal velocity is 14.14 m/s.
Learn more about vertical velocity here: brainly.com/question/24949996
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Answer:
D. The friction force increases by 9600 N.
Explanation:
Frictional force is directly proportional to kinetic coefient of friction.
